jquery获取css的color值返回RGB的方法

a, a:link, a:visited { color:#4188FB; }
a:active, a:focus, a:hover { color:#FFCC00; }

var link_col = $("a:link").css("color");
alert(link_col); // returns rgb(65, 136, 251)

var rgbString = "rgb(0, 70, 255)"; // get this in whatever way.
var parts = rgbString.match(/^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/);
// parts now should be ["rgb(0, 70, 255", "0", "70", "255"]
delete (parts[0]);
for (var i = 1; i <= 3; ++i) {
parts[i] = parseInt(parts[i]).toString(16);
if (parts[i].length == 1) parts[i] = '0' + parts[i];
}
var hexString = parts.join(''); // "0070ff"

function rgb2hex(rgb) {
rgb = rgb.match(/^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/);
function hex(x) {
return ("0" + parseInt(x).toString(16)).slice(-2);
}
return "#" + hex(rgb[1]) + hex(rgb[2]) + hex(rgb[3]);
}