python使用zip将list转为json的方法

> l=[1,2,3,4]
> keys=['a','b','c','d']
> zip(keys,l)
<zip object at 0x000001E0AFA327C8>
> dict(zip(keys,l))
{'a': 1, 'b': 2, 'c': 3, 'd': 4}
> list(zip(keys,l))
[('a', 1), ('b', 2), ('c', 3), ('d', 4)]

# 若参数列表的长度不一样，则以最短长度为准
> m=[1,2,3]
> list(zip(keys,m))
[('a', 1), ('b', 2), ('c', 3)]

# 分解zip
> a1,a2=zip(*zip(keys,l))
> a1
('a', 'b', 'c', 'd')
> a2
(1, 2, 3, 4)
> 

> import json
> l=[[1,2,3,4],[5,6,7,8],[9,10,11,12]]
> keys=['a','b','c','d']
> list_json=[dict(zip(keys,item)) for item in l]
# indent缩进量，ensure_ascii=False支持中文
> str_json=json.dumps(list_json,indent=2, ensure_ascii=False)
> print(str_json)
[
 {
 "a": 1,
 "b": 2,
 "c": 3,
 "d": 4
 },
 {
 "a": 5,
 "b": 6,
 "c": 7,
 "d": 8
 },
 {
 "a": 9,
 "b": 10,
 "c": 11,
 "d": 12
 }
]