JS数组reduce()方法原理及使用技巧解析

var arr = [1, 2, 3, 4];
var sum = arr.reduce((x,y)=>x+y)
var mul = arr.reduce((x,y)=>x*y)
console.log( sum ); //求和，10
console.log( mul ); //求乘积，24

let names = ['Alice', 'Bob', 'Tiff', 'Bruce', 'Alice'];

let nameNum = names.reduce((pre,cur)=>{
 if(cur in pre){
  pre[cur]++
 }else{
  pre[cur] = 1 
 }
 return pre
},{})
console.log(nameNum); //{Alice: 2, Bob: 1, Tiff: 1, Bruce: 1}

let arr = [1,2,3,4,4,1]
let newArr = arr.reduce((pre,cur)=>{
  if(!pre.includes(cur)){
   return pre.concat(cur)
  }else{
   return pre
  }
},[])
console.log(newArr);// [1, 2, 3, 4]

let arr = [[0, 1], [2, 3], [4, 5]]
let newArr = arr.reduce((pre,cur)=>{
  return pre.concat(cur)
},[])
console.log(newArr); // [0, 1, 2, 3, 4, 5]

let arr = [[0, 1], [2, 3], [4,[5,6,7]]]
const newArr = function(arr){
  return arr.reduce((pre,cur)=>pre.concat(Array.isArray(cur)"htmlcode">

var result = [
  {
    subject: 'math',
    score: 10
  },
  {
    subject: 'chinese',
    score: 20
  },
  {
    subject: 'english',
    score: 30
  }
];

var sum = result.reduce(function(prev, cur) {
  return cur.score + prev;
}, 0);
console.log(sum) //60


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